please help me....

Question

a. Plot the pre-image, Triangle WXY: W(0,4), X(-2,-2), Y(1,-3)  

b. Then, rotate the triangle 270° clockwise about the origin creating the image W’X’Y’ 

c. Then, reflect W’X’Y’ across y = -x creating image W”X”Y”

Answer 1

W,X,Y = (0,4),(-2,-2), (1,-3)

W',X',Y' = (-4,0),(2,-2),(3,1)

W",X",Y" = (0,4),(2,-2),(-1,-3)

from W to W' (x,y) becomes (-y,x) so (0,4) becomes (-4,0)

from W' t W" (x,y) becomes (-y,-x) so (-4,0) becomes (0,4)

from W to W" (x,y) becomes (-x,y) so (0,4) stays the same

from X to X" (x,y) becomes (-x,y) so (-2,-2) becomes (2,-2)

from Y to Y" (x,y) becomes (-x,y) so (1,-3) becomes (-1,-3)

from start to finish, just change the sign of the x coordinates

from WXY to W"X"Y", rotate and reflect, only the x coordinate changes sign

the 270 clockwise rotation is the same as a 90 degree counterclockwise rotation

graphically it's easier to visualize the 90 degrees than 270 degrees rotation

Answer 2

Start by plotting the given coordinates of points W, X, and Y on the graph and connect the points to make triangle WXY

In a 270° rotation about the origin, a point (x,y) will transform to (y, -x). So point Y = (1,-3) will become Y' = (-3,-1). You do points W' and X' using the same transformation rule, then plot points W', X', and Y' on the graph and draw triangle W'X'Y':

W' = (?,?))

X' = (?,?)

Y' = (-3,-1)

In a reflection across the line y = -x, the rule is that a point (x,y) will become (-y, -x). So the point Y' = (-3,-1) will become Y" = (1,3). Now you do points W" and X" using the same transformation rule on points W' and X':

W" = (?,?)

X" = (?,?)

Y" = (1.3)

Then plot points W", X", and Y" and draw triangle W"X"Z".