find the solution of equation over the interval [0,2π). 8cos(x)+√3=5√3

Question

find the solution of equation over the interval [0,2π). 8cos(x)+√3=5√3

Answer 1

8cos(x) + sqrt3 = 5sqrt3

8cos(x) = 4sqrt3

cos(x) = (sqrt3)/2

x = pi/6,

x = 11pi/6

taking both the 1st quadrant and 4th quadrant solutions (where cos(x) is positive).