Find the remaining trigonometric ratios. tan(𝛼) = 7, 0 < 𝛼 < 𝜋 2

Answer 1

tanA = 7 = opposite side over adjacent side= 7/1

opposite side=1, adjacent side =1

cotA = 1/tanA = 1/7

A is in either quadrant I or III where all tangents >0

sinA = opposite side over hypotenuse

hypotenuse = sqr(1^2+7^2) = sqr50

sinA = +/-7/sqr(1+49) = +/-7/sqr50

cscA = 1/sinA = +/-sqr50

cosA = adjacent side over hypotenuse

cosA = +/-1/sqr50

secA = 1/cosA = +/- sqr50