<E and <F are supplementary. if m<E= ( 9x -38) and m<f = (2x + 42), find m<F

Question

<E and <F are supplementary. if m<E= ( 9x -38) and m<f = (2x + 42), find m<F

Answer 1

E+F = 180

9x-38 + 2x+42 = 180

11x = 180 -4= 176

x = 176/11 = 16

E=9(16)-38 = 144-38 = 106 degrees

F = 2(16)+42 = 32+42 = 74 degrees

106+74 = 180

supplementary angles sum to 180 degrees

Answer 2

Since E and F are supplementary, E + F = 180.

Therefore, 9x - 38 + 2x + 42 = 180

Moving the constants to one side, we get 11x = 176

Dividing both sides by 11, x = 16

The measure of F is 2(16) + 42 = 74 degrees