90% in the middle of the normal distribution means 5% on one side of the tail (from a table or technology, z = 1.645)
The range is from -z to +z which is 2z
The actual interval is derived from z = (x- μ)/σ
x = μ + zσ or from 6.8 - 1.7z to 6.8 + 1.7z where z = 1.645
The range = 2(1.7)z
Please consider a tutor. Take care.