Let Z be a random variable with a Standard Normal distribution (

Question

Let Z be a random variable with a Standard Normal distribution (). Calculate the following probability. Include all four decimal places in your answer.

 

Answer 1

.385 = about the area between z=0 and z=-1.2

maybe a little less than .68/2 = .34 = .33 about the area between z=0 and z=0.95

add them together: .33 + .385= .715 = area for -1.2 < x < 0.95

for 4 decimal places, use z tables or a z calculator. If you get too different from 0.715 recheck the calculations

if you fall asleep with too many z's, try again later when you're more awake