
Konopelski B. answered 08/17/22
Statistics, Finance, SPSS, SAT Math and physics Tutor
Using default of proportion
P=0.5(since no value is given)
q=1-0.5=0.5
Margin of error =9%=0.09
Z_c=1.65 at 90% confidence interval
margin of error: e= sqrt(p(1-p)/n)*z_c
or, 0.09=sqrt(0.5*0.5/n)*1.65
or, n= (0.5*1.645/0.09)^2=84.0277
The required sample is 84