You are missing three things to solve this problem
1). You need the density of N2
2). The balanced chemical equation
3). Conversion for gallons to ml (1 gal = 3785 ml)
For now, I will write the balanced equation and I will let the density of N2 = 0.543 g/ml
Balanced chemical equation:
2 NaN3 ---------> 2 Na + 3 N2
Start with what's given:
4.0 gal N2 x 3785 ml N2/1 gal N2 = 15140 ml N2
Use the density of N2 to get the grams of N2:
0.543 g/ml x 15140 ml = 8221 g N2
Convert grams of N2 to moles of N2:
8221 g N2 x 1mol N2/28 g N2 = 294 mol N2
Mole-to-mole conversion of N2 to NaN3:
294 mole N2 x 2 mol NaN3/3 mol N2 = 196 mol NaN3
Convert moles of NaN3 to grams of NaN3:
196 mol NaN3 x 65 g NaN3/1 mol NaN3 = 12740 grams