answer this question asap

Question

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t^2+370t+402h

Assuming that the rocket will splash down into the ocean, at what time does splashdown occur?

The rocket splashes down after   _____seconds.

How high above sea-level does the rocket get at its peak?

The rocket peaks at     _____meters above sea-level.

Answer 1

h=-4.9t^2 +307t + 402 = 0

t=307/9.8 + (1/9.8)sqr(307^2+4(4.9)(402))

t = (307 + 319.58)/9,8 = about 63.94 seconds to splash down

h' = -9.8t +307 = 0

t = 307/9.8 = about 31.33 seconds to max height

max height = -4.9(307/9.8)^2 + 307(307/9,8) + 402= about 10,019.24 meters

= about 10 kilometers. some clouds are only 2 km high