J.R. S. answered 08/03/22
Ph.D. University Professor with 10+ years Tutoring Experience
This question requires an understanding of LeChatelier's principle. Since we are dealing with gases, an increase in volume results in a decrease in pressure (when all other variables are constant ). According to LeChatelier, a decrease in pressure (increase in volume) favors that side of the reaction that has the greater moles of gas.
I. 2H2(g) + 02(g) => 2H20 (g) - increase in reactants
II. Ch(g) + PC|3(g) > PC1, (g) - increase in reactants
Ill. H2(g) + 12 (g) > 2HI (g) - no change
V. 2NH; (g) > N2 + 3H2(g) - increase in products