Hi Erika,
X = heights of ten year old children in the United States of Heightlandia.
X is approximately normal with µ=54.3, σ=2.4
a. P(X<55.7) = P(Z<((55.7-54.3)/2.4) = P(Z<0.5833) = 0.720
Using TI84
Using the standard normal
normalcdf(-1000, 0.5833, 0, 1) = 0.720
or
using a normal with µ=54.3, σ=2.4
normalcdf(-1000, 55.7, 54.3, 2.4) = 0.720
b. P(X>49) = P(Z>((49-54.3)/2.4)) = P(Z>-2.208) = 0.986
Using the standard normal
normalcdf(-2.208, 1000, 0, 1) = 0.986
or
using a normal with µ=54.3, σ=2.4
normalcdf(49, 1000, 54.3, 2.4) = 0.986
Let me know if you have any questions
Dian