Raymond B. answered 07/31/22
Math, microeconomics or criminal justice
18R, 24B
p(R) = 18/(18+24) = 18/42 = 3/7
P(2nd R) = 17/41
P(2R) = 3/7 x 17/41 = 51/287= about 18% chance of two red
try a simple similar problem
3 marbles, 2R, 1B
draw 2
there's a chance of 2R or 1R1B
one way to get 2R, two ways to get 1R1B
p(2R)=1/3, p(1R1B) = 2/3
P(first R) = 2/3
P(2nd R) = 1/2
P(2R) = 2/3 x 1/2 = 1/3
multiply the probability of the 1st being Red, times the probability of the 2nd being Red to
get the probability of 2 Reds