Please help! due tonight and I am stumped

Question

In a recent Super Bowl, a TV network predicted that 74 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 65 people who saw the commercials and found that 49 of them said they would watch one of the television shows.

Suppose you have the following null and alternative hypotheses for a test you are running:

H0:p=0.74H0:p=0.74

Ha:p>0.74Ha:p>0.74

Calculate the test statistic, rounded to 3 decimal places

z=

Answer 1

phat = 49/65 = 0.7538

the test statistic, Z = ((0.7538-0.74)/sqrt((0.74*(1-0.74))/65) = 0.254