J.R. S. answered 07/30/22
Ph.D. University Professor with 10+ years Tutoring Experience
The cathode will be the reduction reaction and the anode will be the oxidation reaction.
CATHODE (reduction): Fe3+ + e- ==> Fe2+ unbalance
ANODE (oxidation): Sn ==> Sn2+ + 2e- unbalanced
CATHODE (reduction): 2Fe3+ + 2e- ==> 2Fe2+ balanced
ANODE (oxidation): Sn ==> Sn2+ + 2e- balanced