What is the equilibrium constant K at 25°C for an electrochemical cell when E° = +0.0275 V and n = 2?(F = 96,500 J/(V･mol), R = 8.314 J/(mol･K))

Answer 1

-nFEº = -RT ln K

You are given all the values except K, so plug in the values and solve for K

ln K = -nFEº / -RT and then take the antilog of this answer to get K

Recall that 1 J = 1 CV, i.e. 1 joule = 1 coulomb-volt