J.R. S. answered 07/30/22
Ph.D. University Professor with 10+ years Tutoring Experience
a). Yes. Because it contains elements of the slow step, which is a must.
b). i) rate = k[NO2]
ii) rate = k[CO][O2]
iii) rate = k[N2][O2]
c). O2 is the reaction intermediate
d). Can't draw on this platform, but you'd start with energy of the reactants HIGHER on the y-axis than the energy of the products (exothermic; negative ∆H) and some finite Ea (energy of activation) as a peak