What is ∆G° for a redox reaction where 6 moles of electrons are transferred and E° =-3.65 V? (F = 96,500 J/(V･mol))

Answer 1

You can use the equation ∆Gº = -nFE

n = moles of electrons = 6

F = 96,500 J/Vmol (which is 96.500 coulombs / mole electrons)

Eº = cell voltage = -3.65 V

∆Gº = -(6)(96,500)(-3.65)

∆Gº = 2,113,350 J/mol = 2113 kJ/mol

NOTE: Eº has a negative value (-3.65 V) meaning the redox reaction is not spontaneous. ∆Gº has a positive value which also means the reaction is non spontaneous. These observations are in agreement.