Solving for triangle using Law of Sines

Question

Solve the triangle using the Law of Sines. (Assume b = 3, ∠A = 50°, and ∠C = 110°. Round the lengths to two decimal places, and the angle to the nearest degree.)

Answer 1

Law of Sines: (Sine A°)/ a = (Sine B°)/ b = (Sine C°)/ c

Sum of angles: A° + B° + C° = 180°

50° + B° + 110° = 180°

Measure angle B° = 20°

(Sine 50°)/ a = (Sine 20°) /3 = (Sine 110°)/ c

Value of 'a': 0.766 /a = 0. 342 /3

0.342a = 2.298

a = 6.719

Value of 'c': 0.342/3 = 0.940 /c

0.342c = 2.820

c = 8.260