Inactive Tutor answered 07/23/22
First find angle A by difference from 180
angle A = 180 - 82 - 62 = 36 deg
Then use Law of Sines to find b and c.
SinA/a = SinB/b
Sin36/73.9 = Sin62/b
b = 111.0
SinA/a = SinC/c
Sin36/73.9 = Sin 82/c
c = 125.5
Harris S.
asked 07/23/22Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
a = 73.9, ∠B = 62°, ∠C = 82°
Find what Angle A =
b =
c =
Inactive Tutor answered 07/23/22
First find angle A by difference from 180
angle A = 180 - 82 - 62 = 36 deg
Then use Law of Sines to find b and c.
SinA/a = SinB/b
Sin36/73.9 = Sin62/b
b = 111.0
SinA/a = SinC/c
Sin36/73.9 = Sin 82/c
c = 125.5
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