Mary Ann S. answered 07/24/22
Ph.D. Educational Measurement, Doctoral Minor in Statistics.
Here are some hints to get you started:
1.) You are asked to find the probability of getting >= 3 hits in the game.
2.) You can calculate the probabilities of getting 3 hits, 4 hits, 5 hits, . . . 9 hits or make use of the law of complements and calculate:
1 minus the probability of getting <= 2 hits
3.) calculate the probability of getting exactly 0 hits, 1 hit, or 2 hits and the sum these probabilities to get the probability of getting <= 2 hits. Then fill in that value into the equation in step 2.
4.) Each calculation in determining the probability for 0 hits, 1 hit, or 2 hits followings a binomial distribution, and you can use the binomial formula to calculate it: The p(0 hits) is calculated for you
Let x = number of successes, Let n = number of trials
p(x) = nCx*p^x *(1-p)^(n - x)
p(0) = (9 take 0) * (.32)^0 * (.68)^9 =
p(0) = 1 * 1 * .031087 = .031087
5.) Remember not to round until the end.