a) standard deviation = sqrt(p * (1-p)/n) = sqrt(0.71 * 0.29/229) = 0.03
b) standard deviation = 0.01 = sqrt((0.71 * 0.29)/n)
0.0001 = 0.71 * 0.29/n
0.0001 * n = 0.71 * 0.29
n = 2059
Ben Y.
asked 07/21/22Suppose we take a sample of size 229 from a population with p = 0.71.
What is the standard deviation of the sampling distribution?
Part 2:
Suppose you want to lower the standard deviation to 0.01, what sample size would be needed?
n =
a) standard deviation = sqrt(p * (1-p)/n) = sqrt(0.71 * 0.29/229) = 0.03
b) standard deviation = 0.01 = sqrt((0.71 * 0.29)/n)
0.0001 = 0.71 * 0.29/n
0.0001 * n = 0.71 * 0.29
n = 2059
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