Chemistry Question!

Question

It takes 38 mL of 0.75 M NaOH solution to completely neutralize 155 mL of a sulfuric acid solution (H2SO4). What is the concentration of the H2SO4 solution?

Please state detailed computation. Thank you!

Answer 1

2NaOH + H2SO4 ==> Na2SO4 + 2H2O ... balanced equation for the reaction taking place

mols NaOH used = 38 ml x 1 L / 1000 ml x 0.75 mol / L = 0.0285 mols NaOH used

mols H2SO4 present = 0.0285 mols NaOH x 1 mol H2SO4 / 2 mol NaOH = 0.01425 mols H2SO4 present

Concentration H2SO4 = mols/liter = 0.01425 mols / 155 ml x 1000 ml / L = 0.0919 M = 0.092 M (2 s.f.)