How long, in seconds, would it take for the concentration of A to decrease from 0.820 M to 0.350 M?

Question

The rate constant for this second‑order reaction is 0.460 M−1⋅s−10.460⁢ M−1⋅s−1 at 300 ∘C.300⁢ ∘C.

A⟶productsA⟶products

How long, in seconds, would it take for the concentration of AA to decrease from 0.820 M0.820 M to 0.350 M?

Answer 1

The integrated rate equation for a 2nd order reaction is

1/[A] = 1/[A]_o + kt

1/[0.350] = 1/[0.820] + (0.460)t

2.857 = 1.220 + 0.460t

0.460t = 1.637

t = 3.56 sec