J.R. S. answered 07/11/22
Ph.D. University Professor with 10+ years Tutoring Experience
q = m∆Hfus
q = heat = ?
m = mass = 40.6 g = 40.6 g x 1 mol/119 g = 0.341 mol
∆Hfus = enthalpy of fusion = 7.07 kJ/mol
q = (0.341 mol)(7.07 kJ/mol)
q = 2.41 kJ
Arciene B.
asked 07/11/22Given the following information for tin, Sn (at 1 atm), calculate the amount of heat in kJ needed (at 1 atm) to melt a 40.6-g sample of solid tin at its normal melting point of 232 °C.
| boiling point = 2.27×103 °C |
Hvap(2.27×103 °C) = 230 kJ/mol
|
| melting point = 232 °C |
Hfus(232 °C) = 7.07 kJ/mol
|
| specific heat liquid = 0.243 J/g°C |
_____kJ
J.R. S. answered 07/11/22
Ph.D. University Professor with 10+ years Tutoring Experience
q = m∆Hfus
q = heat = ?
m = mass = 40.6 g = 40.6 g x 1 mol/119 g = 0.341 mol
∆Hfus = enthalpy of fusion = 7.07 kJ/mol
q = (0.341 mol)(7.07 kJ/mol)
q = 2.41 kJ
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.