J.R. S. answered 07/09/22
Ph.D. University Professor with 10+ years Tutoring Experience
Sodium iodide = NaI
Total mass of the solution = 5.80 g NaI + 17.3 g H2O = 23.1 g
Weight/weight % NaI = mass NaI / total mass of solution (x100%
Weight/weight % NaI = 5.80 g / 23.1 g (x100%)
Weight/weight % NaI = 25.1%