Chima M.
asked 07/08/22Can I get help on this
The chemical reaction shown was performed and the concentration of HClHCl was measured over time.
Cl2(g)+CHCl3(g)⟶HCl(g)+CCl4(g)Cl2(g)+CHCl3(g)⟶HCl(g)+CCl4(g)
The [HCl][HCl] after 11 s11 s was 0.184 mol/L0.184 mol/L . After 146 s146 s , the [HCl][HCl] was 0.451 mol/L0.451 mol/L .
Calculate the rate of reaction.
rate of reaction: mol HCl/L/s?
1 Expert Answer
J.R. S. answered 07/09/22
Ph.D. University Professor with 10+ years Tutoring Experience
If you are looking for the average rate of the reaction over this time period, it would be calculated as follows:
∆[HCl] / ∆t
∆[HCl] = 0.451 M - 0.184 M = 0.267 M
∆t = 146 s - 11 s = 135 s
Rate = 0.267 M / 135 s = 0.00198 M/s
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Chima M.
I Apologize. I accidently put Cl2(g)+CHCl3(g)⟶HCl(g)+CCl4, 11 s, 0.184 mol/L, 146 s, [HCl], and 0.451 mol/L twice.07/08/22