What is the approximate percentage of students who scored between 46 and 70 on the test? Round to two decimal places.

Question

The maximum possible score on the test was 110, while the mean score was 70 and the standard deviation was 8.

Is the answer 0.5?

Answer 1

P(46 x < 70) = P( (46-70)/8 < z < (70 - 70)/8) = P(-3 < z < 0) = P(z < 0) - P(z < -3) = 0.5 - 0.0013 = 0.0487