What is ∆G° for the reaction 3 O₂(g) → 2 O₃(g) at 25°C (or 298 K) if K = 6.1 x 10⁻⁵⁸? (R = 8.314. J/mol ･ K)

Answer 1

∆Gº = -RT ln K

∆Gº = -(8.314 J/molK)(298K) ln 6.1x10^-58

∆Gº = -2477.57 x -131.74

∆Gº = 326,395 J/mol = 326 kJ/mol (3 sig.figs.)