J.R. S. answered • 07/07/22
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∆Gº = -RT ln K
∆Gº = 223.5 kJ/mol
R = 8.314 J/Kmol x 1 kJ/1000 J = 0.008134 kJ/Kmol (to get units to agree with those of ∆Gº)
T = 25.0ºC + 273.15 = 298.15K
K = ?
Substituting known values and solving for K:
223.5 = -(0.008314)(298.15) ln K
223.5 = -2.4788 ln K
ln K = -90.16
K = 6.98x10-40
J.R. S.
tutor
Are you asking how to go from ln K = -90.16 to K = 6.98x10^-40? I took the anti ln and to check, if you take ln 6.98x10^-40, you get -90.16. On my calculator i entered -90.16, the entered e^x. Not being a math person, I hope I'm explaining it properly.
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10/26/23
Efosa A.
Im stuck on the last step how did you get the final answer10/24/23