J.R. S. answered 07/05/22
Ph.D. University Professor with 10+ years Tutoring Experience
H2S(g) <==> H2(g) + S(g) ... balanced equation
Kp = (H2)(S) / (H2S)
Kp = (0.0351)(0.0251) / (0.0353)
Kp = 0.0250
Katelyn A.
asked 07/04/22At 2000 K the partial pressures of an equilibrium mixture of H2S, H2, and S are 0.0353 , 0.0351 , and 0.0251 atm, respectively. Calculate the value of the equilibrium constant Kp at 2000 K.
H2S(g)H2(g)+S(g)
J.R. S. answered 07/05/22
Ph.D. University Professor with 10+ years Tutoring Experience
H2S(g) <==> H2(g) + S(g) ... balanced equation
Kp = (H2)(S) / (H2S)
Kp = (0.0351)(0.0251) / (0.0353)
Kp = 0.0250
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