Use a system of equations to solve. The sum of three Integers is 62. The sum of the first and second integers exceeds the third by 86. The third integer is 6S less than the first. Find the 3 integers.

Answer 1

x+y+z = 62

x +y = z+86

z = x-6

use elimination, substitution or matrix algebra to solve for x,y, and z, the 1st, 2nd & 3rd integers

z+86 +z = 62

2z = 62-86 = - 24

z= -24/2 = -12

x=z+6 = -6

y=80

-6, 80 and -12

that worked out, but instead of 6 you seem to have 65. that 5 looks like a mistaken S typo

so if it's 65 then

do the same basic calculations but they come out to

53, 21, -12 for 1st, 2nd and 3rd integers