J.R. S. answered 07/03/22
Ph.D. University Professor with 10+ years Tutoring Experience
HClO2 <==> H+ + ClO2- ... Ka = 0.011
Ka = [H+][ClO2-] / [HClO2]
0.011 = (x)(x) / 0.215 - x
x2 = 0.002365 - 0.011x
x2 + 0.011x - 0.002365 = 0
x = 0.0434 M = [H+]
pH = -log [H+]
pH = -log 0.0434
pH = 1.36