All segements that look tangent, are tangent to the circle. AL = 12, BK = 11, and AJ = 10. Find the perimeter of the triangle.

Question

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Answer 1

Hi Evan!

There is a property that states that two tangent segments to a circle from the same point outside the circle will always be congruent.

Thus, in your problem, BJ=AJ=10, CK=BK=11, and CL=AL=12. So the 3 sides of the triangle are LJ=10+1=22, JK=10+11=21, and LK=12+11=23. So the perimeter is 22+21+23=66.

Hope that helps!