P(xbar > 168) = P(z > (xbar - mu)/(SD/sqrt(sample size)) = P(z < (168 - 174)/(31/sqrt(12) = P(z > -0.67) = P(z < 0.67) = 0.7486
Kylie M.
asked 07/01/22What is the probability the elevator is overloaded?
An elevator has a placard stating that the maximum capacity is 2016 lb- 12 passengers. So, 12 adult male passengers can have a mean weight of up to 2016/12=168 pounds If the elevator is loaded with 12 adult male passengers, find the probability that it is overloaded because they have a mean weight greater than 168 lb. (Assume that weights of males are normally distributed with a mean of 174 lb and a standard deviation of 31 lb.) Does this elevator appear to be safe?
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