J.R. S. answered 06/29/22
Ph.D. University Professor with 10+ years Tutoring Experience
Combined Gas Law: P1V1/T1 = P2V2/T2
P1 = initial pressure = 645.3 mm Hg
V1 = initial volume = 0.606 L
T1 = initial temperature = 21.5ºC + 273 = 294.5K
P2 = final pressure = ?
V2 = final volume = 2060 ml x 1 L / 1000 ml = 2.060 L
T2 = final temperature = 26.8ºC + 273 = 299.8K
Solving for P2, we have ...
P2 = P1V1T2 / V2T1
P2 = (645.3)(0.606)(299.8) / (2.060)(294.5)
P2 = 193 mm Hg
If you want the final pressure in atm, simply divide by 760