J.R. S. answered 06/24/22
Ph.D. University Professor with 10+ years Tutoring Experience
2HgO(s) ==> 2Hg(l) + O2(g) ... balanced equation
molar mass HgO = 216.6 g / mol
molar mass O2 = 32 g / mol
Use stoichiometry (mol ratio) of the balanced equation along with dimensional analysis to calculate:
20.00 g HgO x 1 mol HgO / 216.6 g x 1 mol O2 / 2 mol HgO x 32 g O2 / mol = 1.477 g O2 (4 sig.figs.)