probability of m&ms

Question

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) 

If you randomly select six peanut M&M’s, compute that probability that at least one of them is orange. 

Answer 1

P(at least 1 orange) = 1 - P(no orange in 6 tries) = 1 - P⁶(Orange in 1 try) = 1 - (.23)⁶ assuming that there are enough M&Ms so that we can treat the problem as allowing replacement.

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