Martin P. answered 06/23/22
Tutor
5.0
(587)
graduate chemistry work, Doctorate degree, Former College Professor
pH = -log [H3O*]
Given: [H3O+} = 4.5 x 10-2M
pH = -log4.5 x10-2
pH = 1.35
Denise M.
asked 06/23/22pls provide all steps have no idea how to do this thank you
Martin P. answered 06/23/22
graduate chemistry work, Doctorate degree, Former College Professor
pH = -log [H3O*]
Given: [H3O+} = 4.5 x 10-2M
pH = -log4.5 x10-2
pH = 1.35
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