calculate the PH of [OH-]=5.9x 10-3 M

Question

pls provide steps so i can learn... have never done this before and thank you

Answer 1

The pH = -log[H3O+1]

The pOH = -log[OH-]

pH + pOH = 14

Given: [OH-] = 5.9 x 10-3M

Step 1) Find the pOH

pOH = -log[OH-]

pOH = -log5.9x10-3M = 2.23

Step 2) pH + pOH = 14

pH + 2.23. = 14

pH = 14 - 2.223

pH = 11.77