Denise M.
asked 06/23/22how to calculate the ph of this solution [OH-]=5x10-2M
pls provide all steps so I can learn thank you
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1 Expert Answer
J.R. S. answered 06/23/22
Tutor
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Ph.D. University Professor with 10+ years Tutoring Experience
pH = -log [H+]
pOH = -log [OH-]
pH + pOH = 14
One method:
pOH = -log 5x10-2 = 1.30
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 1.30
pH = 12.7
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Denise M.
I got 12.7 wrong. 1st needs to be two sig figs and this was to be calculated for the [H3O] value of the solution06/24/22