J.R. S. answered 06/22/22
Ph.D. University Professor with 10+ years Tutoring Experience
8.) Bismuth (Bi), atomic number = 83, so it has 83 protons and 83 electrons. It is a "p block" element in period 6 and group 15, so it will have 5 valence electrons, the last of which will be in the 6p sublevel, and the noble gas electron configuration will use [Xe] and is ...
[Xe] 4f14 5d10 6s2 6p3
principal (n) = 6
azimuthal (l) = 1
magnetic (ml) = -1, 0, +1
spin (s) = +1/2, -1/2
9.) Tin (Sn), atomic number = 50, so it has 50 protons and 50 electrons. It is a "p block" element in period 5 and group 14, so it will have 4 valence electrons, the last of which will be in the 5 p sublevel, and the noble gas electron configuration will use [Kr] and is ...
[Kr] 4d10 5s2 5p2
principal (n) = 5
azimuthal (l) = 1
magnetic (ml) = -1, 0, +1
spin (s) = +1/2, -1/2