J.R. S. answered 06/22/22
Ph.D. University Professor with 10+ years Tutoring Experience
Since the scuba tank is of a fixed volume, as the temperature increases, the pressure inside the tank will increase. We can use Gay-Lussac's law:
P1 / T1 = P2 / T2
P1 = initial pressure = 16.7 atm
T1 = initial temperature in Kelvin = 24ºC + 273 = 297K
P2 = final pressure = ?
T2 = final temperature in Kelvin = 65ºC + 273 = 338K
Solving for P2 we have ...
P2 = P1T2 / T1
P2 = (16.7 atm)(338K) / 297K
P2 = 19.0 atm