Raymond B. answered 06/20/22
Math, microeconomics or criminal justice
2cos^2(T) - cosT -1 = 0
let x=cosT
2x^2 -x -1 = 0
factor
(2x+1)(x-1) = 0
set each factor = 0 and solve for x
2x+1=0, x =-1/2
x-1 = 0, x = 1
x=cosT
cosT = -1/2 or 1
T = (..., -2pi, -4pi/3, 0, 2pi/3, pi, 5pi/3, 2pi, 8pi/3, .... , 2kpi, 2pi/3+2kpi, ... ) where k= any integer
or theta = (120k, 360k) in degrees, where k = any integer, positive or negative
or theta = (2kpi, 2pi/3+2kpi) in radians were k = any integer