Calorimetry - Chemistry

Question

A 25.00 gram sample of an unknown metal initially at 99.0 degrees Celcius is added to 50.00 grams of water initially at 7.16 degrees Celcius. The final temperature of the system is 20.15 degrees Celcius. Calculate the specific heat of the metal.

*The specific heat of water is 4.184 

Answer 1

heat lost by metal equal heat gained by water

heat lost by metal = q = mC∆T = (25.00 g)(C)(78.85º)

heat gained by water = q = mC∆T = (50.00 g)(4.194 J/gº)(12.99º) = 2718 J

2718 J = (25.00 g)(C)(78.85º)

2718 J = 1971 C

C = specific heat of metal = 1.379 J/gº