J.R. S. answered 06/20/22
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
266.98 J = (57.46 g)(C)(49.3º)
C = 0.0942 J/gº = specific heat of the unknown
Julia D.
asked 06/20/22An unknown sample is being evaluated in lab. What is the specific heat capacity of the compound if it requires 266.98 J to raise the temperature of 57.46 grams of the unknown from 15.2 °C to 64.5 °C.
J.R. S. answered 06/20/22
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
266.98 J = (57.46 g)(C)(49.3º)
C = 0.0942 J/gº = specific heat of the unknown
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