Calorimetry - Chemistry

Question

How much heat (in joules) is used to heat a 76.60 gram sample of iron from 11.0 degrees Celcius to 100.00 degrees Celcius if the specific heat of Fe is 0.450 ^J/_g°C?

Answer 1

For this type of problem, we use the equation q = mC∆T

q = heat = ?

m = mass = 76.60 g

C = specific heat = 0.450 J/gº

∆T = change in temperature = 100.00º - 11.0º = 89.0º

Solving for q, we have

q = (76.60 g)(0.450 J/gº)(89.0º)

q = 3068 J = 3070 J (3 sig. figs.)