J.R. S. answered 06/20/22
Ph.D. University Professor with 10+ years Tutoring Experience
First, we must write a correctly balanced equation for the reaction taking place.
2 C4H10 + 13 O2 ==> 8 CO2 + 10 H2O ... balanced equatin
Next, we find the MOLES of C4H10, then moles CO2 produced, and finally grams CO2 produced.
molar mass C4H10 = 58 g / mol
molar mass CO2 = 44 g / mol
2.43 g C4H10 x 1 mol / 58 g = 0.0419 mols C4H10
0.0419 mol C4H10 x 8 mol CO2 / 2 mol C4H10 = 0.168 mol CO2
0.168 mol CO2 x 44 g CO2 / mol = 7.37 g CO2 produced