Mark M. answered 06/16/22
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
2 cos 3θ sin 2θ - sin 2θ = 0
sin 2θ (2 cos 3θ - 1) = 0
Now use Zero Product Rule (Algebra 2) to solve for θ.
0000 A.
asked 06/16/222 cos (3θ) sin (2θ) − sin (2θ) = 0
Mark M. answered 06/16/22
Mathematics Teacher - NCLB Highly Qualified
2 cos 3θ sin 2θ - sin 2θ = 0
sin 2θ (2 cos 3θ - 1) = 0
Now use Zero Product Rule (Algebra 2) to solve for θ.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.