Find all angles θ that are solutions of the equation. Express the solutions in degree measurement.

Question

sqrtθ sec(θ/2)+ 2 = 0

Answer 1

sqrtθ sec(θ/2)+ 2 = 0

need to solve in radians

anyhow, the graphs y1=(-2)/√x

and y2=sec(x/2) do not intersect so there is no answer

(they come close to intersecting at θ=6 radians)

check √6*sec(3)=-2.48

if the equation was sqrtθ sec(θ/2)- 2 = 0

then θ=1.715 radians approximately is a solution

1.715 radians = about 98.26 degrees