Describe how are you going to prepare 100 mL of 6M HCl solution from 32% to 38% HCl solution

Question

Concentration needed: 6M solution

Volume needed: 100 mL

Concentration available: 32% - 38%

Please state a complete detailed solution. Please help me ASAP

Answer 1

Calculations:

You are given % HCl and you want to make a molar (6 M) solution of HCl. We will assume that the 32-38% HCl is mass/volume. So, for example, 32% HCl (m/v) = 32 g HCl / 100 ml

To make 100 ml of 6 M HCl, that is equal to 0.1 L of 6 M

0.1 L x 6 mol / L = 0.6 mol HCl needed

molar mass HCl = 36.5 g / mol

0.6 mol HCl x 36.5 g / mol = 21.9 g HCl needed

How to get 21.9 g HCl from a solution that is 32 g / 100 ml?

21.9 g HCl x 100 ml / 32 g HCl = 68.4 ml

Procedure:

Measure 68.4 ml of 32% (m/v) HCl and dilute this to a final volume of 100 ml